n(3n-3)-5(3+n)=3n^2+2n+3

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Solution for n(3n-3)-5(3+n)=3n^2+2n+3 equation: 



n(3n-3)-5(3+n)=3n^2+2n+3

We move all terms to the left:

n(3n-3)-5(3+n)-(3n^2+2n+3)=0

We add all the numbers together, and all the variables

n(3n-3)-5(n+3)-(3n^2+2n+3)=0

We multiply parentheses

3n^2-3n-5n-(3n^2+2n+3)-15=0

We get rid of parentheses

3n^2-3n^2-3n-5n-2n-3-15=0

We add all the numbers together, and all the variables

-10n-18=0

We move all terms containing n to the left, all other terms to the right

-10n=18

n=18/-10

n=-1+4/5

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